Integrand size = 22, antiderivative size = 104 \[ \int \frac {1}{(a+b x)^3 \left (a^2-b^2 x^2\right )^2} \, dx=\frac {1}{32 a^5 b (a-b x)}-\frac {1}{16 a^2 b (a+b x)^4}-\frac {1}{12 a^3 b (a+b x)^3}-\frac {3}{32 a^4 b (a+b x)^2}-\frac {1}{8 a^5 b (a+b x)}+\frac {5 \text {arctanh}\left (\frac {b x}{a}\right )}{32 a^6 b} \]
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Time = 0.04 (sec) , antiderivative size = 104, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.136, Rules used = {641, 46, 214} \[ \int \frac {1}{(a+b x)^3 \left (a^2-b^2 x^2\right )^2} \, dx=\frac {5 \text {arctanh}\left (\frac {b x}{a}\right )}{32 a^6 b}+\frac {1}{32 a^5 b (a-b x)}-\frac {1}{8 a^5 b (a+b x)}-\frac {3}{32 a^4 b (a+b x)^2}-\frac {1}{12 a^3 b (a+b x)^3}-\frac {1}{16 a^2 b (a+b x)^4} \]
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Rule 46
Rule 214
Rule 641
Rubi steps \begin{align*} \text {integral}& = \int \frac {1}{(a-b x)^2 (a+b x)^5} \, dx \\ & = \int \left (\frac {1}{32 a^5 (a-b x)^2}+\frac {1}{4 a^2 (a+b x)^5}+\frac {1}{4 a^3 (a+b x)^4}+\frac {3}{16 a^4 (a+b x)^3}+\frac {1}{8 a^5 (a+b x)^2}+\frac {5}{32 a^5 \left (a^2-b^2 x^2\right )}\right ) \, dx \\ & = \frac {1}{32 a^5 b (a-b x)}-\frac {1}{16 a^2 b (a+b x)^4}-\frac {1}{12 a^3 b (a+b x)^3}-\frac {3}{32 a^4 b (a+b x)^2}-\frac {1}{8 a^5 b (a+b x)}+\frac {5 \int \frac {1}{a^2-b^2 x^2} \, dx}{32 a^5} \\ & = \frac {1}{32 a^5 b (a-b x)}-\frac {1}{16 a^2 b (a+b x)^4}-\frac {1}{12 a^3 b (a+b x)^3}-\frac {3}{32 a^4 b (a+b x)^2}-\frac {1}{8 a^5 b (a+b x)}+\frac {5 \tanh ^{-1}\left (\frac {b x}{a}\right )}{32 a^6 b} \\ \end{align*}
Time = 0.03 (sec) , antiderivative size = 112, normalized size of antiderivative = 1.08 \[ \int \frac {1}{(a+b x)^3 \left (a^2-b^2 x^2\right )^2} \, dx=\frac {-64 a^5-30 a^4 b x+70 a^3 b^2 x^2+90 a^2 b^3 x^3+30 a b^4 x^4-15 (a-b x) (a+b x)^4 \log (a-b x)+15 (a-b x) (a+b x)^4 \log (a+b x)}{192 a^6 b (a-b x) (a+b x)^4} \]
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Time = 2.29 (sec) , antiderivative size = 96, normalized size of antiderivative = 0.92
method | result | size |
norman | \(\frac {\frac {27 x}{32 a^{2}}+\frac {33 b \,x^{2}}{32 a^{3}}-\frac {19 b^{2} x^{3}}{96 a^{4}}-\frac {27 b^{3} x^{4}}{32 a^{5}}-\frac {b^{4} x^{5}}{3 a^{6}}}{\left (b x +a \right )^{4} \left (-b x +a \right )}-\frac {5 \ln \left (-b x +a \right )}{64 a^{6} b}+\frac {5 \ln \left (b x +a \right )}{64 a^{6} b}\) | \(96\) |
risch | \(\frac {\frac {5 b^{3} x^{4}}{32 a^{5}}+\frac {15 b^{2} x^{3}}{32 a^{4}}+\frac {35 b \,x^{2}}{96 a^{3}}-\frac {5 x}{32 a^{2}}-\frac {1}{3 b a}}{\left (b x +a \right )^{3} \left (-b^{2} x^{2}+a^{2}\right )}-\frac {5 \ln \left (-b x +a \right )}{64 a^{6} b}+\frac {5 \ln \left (b x +a \right )}{64 a^{6} b}\) | \(99\) |
default | \(\frac {5 \ln \left (b x +a \right )}{64 a^{6} b}-\frac {1}{8 a^{5} b \left (b x +a \right )}-\frac {3}{32 a^{4} b \left (b x +a \right )^{2}}-\frac {1}{12 a^{3} b \left (b x +a \right )^{3}}-\frac {1}{16 a^{2} b \left (b x +a \right )^{4}}-\frac {5 \ln \left (-b x +a \right )}{64 a^{6} b}+\frac {1}{32 a^{5} b \left (-b x +a \right )}\) | \(107\) |
parallelrisch | \(-\frac {15 \ln \left (b x -a \right ) x^{5} b^{5}-15 \ln \left (b x +a \right ) x^{5} b^{5}+45 \ln \left (b x -a \right ) x^{4} a \,b^{4}-45 \ln \left (b x +a \right ) x^{4} a \,b^{4}-64 b^{5} x^{5}+30 \ln \left (b x -a \right ) x^{3} a^{2} b^{3}-30 \ln \left (b x +a \right ) x^{3} a^{2} b^{3}-162 a \,b^{4} x^{4}-30 \ln \left (b x -a \right ) x^{2} a^{3} b^{2}+30 \ln \left (b x +a \right ) x^{2} a^{3} b^{2}-38 a^{2} b^{3} x^{3}-45 \ln \left (b x -a \right ) x \,a^{4} b +45 \ln \left (b x +a \right ) x \,a^{4} b +198 a^{3} b^{2} x^{2}-15 a^{5} \ln \left (b x -a \right )+15 a^{5} \ln \left (b x +a \right )+162 a^{4} b x}{192 a^{6} \left (b x +a \right )^{3} \left (b^{2} x^{2}-a^{2}\right ) b}\) | \(264\) |
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Leaf count of result is larger than twice the leaf count of optimal. 227 vs. \(2 (93) = 186\).
Time = 0.32 (sec) , antiderivative size = 227, normalized size of antiderivative = 2.18 \[ \int \frac {1}{(a+b x)^3 \left (a^2-b^2 x^2\right )^2} \, dx=-\frac {30 \, a b^{4} x^{4} + 90 \, a^{2} b^{3} x^{3} + 70 \, a^{3} b^{2} x^{2} - 30 \, a^{4} b x - 64 \, a^{5} - 15 \, {\left (b^{5} x^{5} + 3 \, a b^{4} x^{4} + 2 \, a^{2} b^{3} x^{3} - 2 \, a^{3} b^{2} x^{2} - 3 \, a^{4} b x - a^{5}\right )} \log \left (b x + a\right ) + 15 \, {\left (b^{5} x^{5} + 3 \, a b^{4} x^{4} + 2 \, a^{2} b^{3} x^{3} - 2 \, a^{3} b^{2} x^{2} - 3 \, a^{4} b x - a^{5}\right )} \log \left (b x - a\right )}{192 \, {\left (a^{6} b^{6} x^{5} + 3 \, a^{7} b^{5} x^{4} + 2 \, a^{8} b^{4} x^{3} - 2 \, a^{9} b^{3} x^{2} - 3 \, a^{10} b^{2} x - a^{11} b\right )}} \]
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Time = 0.31 (sec) , antiderivative size = 133, normalized size of antiderivative = 1.28 \[ \int \frac {1}{(a+b x)^3 \left (a^2-b^2 x^2\right )^2} \, dx=\frac {32 a^{4} + 15 a^{3} b x - 35 a^{2} b^{2} x^{2} - 45 a b^{3} x^{3} - 15 b^{4} x^{4}}{- 96 a^{10} b - 288 a^{9} b^{2} x - 192 a^{8} b^{3} x^{2} + 192 a^{7} b^{4} x^{3} + 288 a^{6} b^{5} x^{4} + 96 a^{5} b^{6} x^{5}} + \frac {- \frac {5 \log {\left (- \frac {a}{b} + x \right )}}{64} + \frac {5 \log {\left (\frac {a}{b} + x \right )}}{64}}{a^{6} b} \]
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Time = 0.20 (sec) , antiderivative size = 135, normalized size of antiderivative = 1.30 \[ \int \frac {1}{(a+b x)^3 \left (a^2-b^2 x^2\right )^2} \, dx=-\frac {15 \, b^{4} x^{4} + 45 \, a b^{3} x^{3} + 35 \, a^{2} b^{2} x^{2} - 15 \, a^{3} b x - 32 \, a^{4}}{96 \, {\left (a^{5} b^{6} x^{5} + 3 \, a^{6} b^{5} x^{4} + 2 \, a^{7} b^{4} x^{3} - 2 \, a^{8} b^{3} x^{2} - 3 \, a^{9} b^{2} x - a^{10} b\right )}} + \frac {5 \, \log \left (b x + a\right )}{64 \, a^{6} b} - \frac {5 \, \log \left (b x - a\right )}{64 \, a^{6} b} \]
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Time = 0.28 (sec) , antiderivative size = 101, normalized size of antiderivative = 0.97 \[ \int \frac {1}{(a+b x)^3 \left (a^2-b^2 x^2\right )^2} \, dx=\frac {5 \, \log \left ({\left | b x + a \right |}\right )}{64 \, a^{6} b} - \frac {5 \, \log \left ({\left | b x - a \right |}\right )}{64 \, a^{6} b} - \frac {15 \, a b^{4} x^{4} + 45 \, a^{2} b^{3} x^{3} + 35 \, a^{3} b^{2} x^{2} - 15 \, a^{4} b x - 32 \, a^{5}}{96 \, {\left (b x + a\right )}^{4} {\left (b x - a\right )} a^{6} b} \]
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Time = 9.56 (sec) , antiderivative size = 115, normalized size of antiderivative = 1.11 \[ \int \frac {1}{(a+b x)^3 \left (a^2-b^2 x^2\right )^2} \, dx=\frac {\frac {35\,b\,x^2}{96\,a^3}-\frac {1}{3\,a\,b}-\frac {5\,x}{32\,a^2}+\frac {15\,b^2\,x^3}{32\,a^4}+\frac {5\,b^3\,x^4}{32\,a^5}}{a^5+3\,a^4\,b\,x+2\,a^3\,b^2\,x^2-2\,a^2\,b^3\,x^3-3\,a\,b^4\,x^4-b^5\,x^5}+\frac {5\,\mathrm {atanh}\left (\frac {b\,x}{a}\right )}{32\,a^6\,b} \]
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